超时错误

• 扩展：错误

每当某些操作由于超时而终止时，例如 locator.waitFor() 或 browserType.launch()，就会发出 TimeoutError。

const playwright = require('playwright');

(async () => {
  const browser = await playwright.chromium.launch();
  const context = await browser.newContext();
  const page = await context.newPage();
  try {
    await page.locator('text=Foo').click({
      timeout: 100,
    });
  } catch (error) {
    if (error instanceof playwright.errors.TimeoutError)
      console.log('Timeout!');
  }
  await browser.close();
})();