超时错误

• 扩展: [错误]

当某些操作由于超时而终止时，例如 Locator.WaitForAsync() 或 BrowserType.LaunchAsync()，会发出 TimeoutError。

using Microsoft.Playwright;

using var playwright = await Playwright.CreateAsync();
await using var browser = await playwright.Chromium.LaunchAsync();
var page = await browser.NewPageAsync();
try
{
    await page.ClickAsync("text=Example", new() { Timeout = 100 });
}
catch (TimeoutException)
{
    Console.WriteLine("Timeout!");
}